Topics › Percentage › Q127
During the school Green Week, Ali collected 25% more recycling points than Mei Ling. What percentage fewer recycling points did Mei Ling collect than Ali? Use a concrete number to check your answer.
Try it yourself · watch the animation →Let Mei Ling be 100 parts, so Ali is 125 parts. When finding “fewer than Ali”, use Ali’s 125 parts as the denominator.
Answer: Mei Ling collected 20% less %
Method: When B is p% more than A, draw A as 100 parts and B as 100 + p parts. To find what percentage less A is than B, divide the difference p by B’s 100 + p parts.
33 1/3% less % — Let Siti’s number of questions be 100 parts. Raju did 50% more, so Raju did 150 parts. The difference is 150 − 100 = 50 parts. Siti did fewer than Raju by: 50 ÷ 150 × 100% = 33 1/3%.
37.5% shorter % — Drink stall queue = 100 parts. The noodle stall queue is 60% longer, so it is 160 parts. The difference is 60 parts. The drink stall queue was shorter than the noodle stall queue by: 60 ÷ 160 × 100% = 37.5%.
180 marbles, 20% fewer % — Ali had 25% more than Siti, and the extra 25% is 45 marbles. Siti’s 100% = 45 ÷ 25 × 100 = 180 marbles. Ali had 180 + 45 = 225 marbles. Siti had fewer than Ali by: 45 ÷ 225 × 100% = 20%.
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