For the school open house, Siti makes a rectangular notice board. Its length is (3y + 8) cm and its breadth is (y + 4) cm. (a) Express its perimeter in terms of y. (b) Express its area in terms of y and simplify it. (c) Find the perimeter and area when y = 6.
Try it yourself · watch the animation →A rectangle has two lengths and two breadths. First write perimeter = length + breadth + length + breadth, and area = length × breadth, then expand and simplify.
Answer: Perimeter expression 8y+24 cm; Area expression 3y^2+20y+32 cm²; Perimeter when y = 6 72 cm; Area when y = 6 260 cm²
Method: Label all four sides first. Add the four sides and simplify for the perimeter; multiply length by breadth, then expand and collect like terms for the area. Then substitute the value of y.
0 cm, 0 cm², 58 cm, 190 cm² — Perimeter P = 2(2y + 5) + 2(y + 3) = 4y + 10 + 2y + 6 = 6y + 16. Area A = (2y + 5)(y + 3) = 2y² + 6y + 5y + 15 = 2y² + 11y + 15. When y = 7, length = 2 × 7 + 5 = 19 cm and breadth = 7 + 3 = 10 cm. Perimeter = 6 × 7 + 16 = 58 cm; area = 19 × 10 = 190 cm².
0 m, 0 m², 56 m, 187 m² — Perimeter P = 2(4y - 3) + 2(2y + 1) = 8y - 6 + 4y + 2 = 12y - 4. Area A = (4y - 3)(2y + 1) = 8y² + 4y - 6y - 3 = 8y² - 2y - 3. When y = 5, length = 4 × 5 - 3 = 17 m and breadth = 2 × 5 + 1 = 11 m. Perimeter = 12 × 5 - 4 = 56 m; area = 17 × 11 = 187 m².
0 m, 0 m², 144 m, 1175 m² — Perimeter P = 2(5y + 2) + 2(2y + 7) = 10y + 4 + 4y + 14 = 14y + 18. Area A = (5y + 2)(2y + 7) = 10y² + 35y + 4y + 14 = 10y² + 39y + 14. When y = 9, length = 5 × 9 + 2 = 47 m and breadth = 2 × 9 + 7 = 25 m. Perimeter = 14 × 9 + 18 = 144 m; area = 47 × 25 = 1175 m².
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